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hw3 [2016/04/16 10:25] – [Journal reading (5 pts)] janethw3 [2020/03/06 09:14] (current) – external edit 127.0.0.1
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 $$R = {h \over {2{e^2}}}{L \over {{\ell _{ph}}}}$$ $$R = {h \over {2{e^2}}}{L \over {{\ell _{ph}}}}$$
  
-**c)** Show that the the above result is equivalent to the Drude formula, within a factor of 2, if we assume a free electron dispersion relation $E = {{{\hbar ^2}{k^2}} \over {2m}}$.+**c)** Show that the above result is equivalent to the Drude formula, within a factor of 2, if we assume a free electron dispersion relation $E = {{{\hbar ^2}{k^2}} \over {2m}}$.
  
 $${\rho _{1d}} = {m \over {{n_{1d}}{e^2}{\tau _{e - ph}}}}$$ $${\rho _{1d}} = {m \over {{n_{1d}}{e^2}{\tau _{e - ph}}}}$$
hw3.1460827521.txt.gz · Last modified: 2020/03/06 09:14 (external edit)